Hi, i'm having trouble with this problem. The question is: expand the function f(x)=x where x belongs to [0,2pi] into a real fourier series. Any help would be much appreciated thanks.

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- Nov 24th 2008, 06:51 AMmbbx5va2Fourier series question
Hi, i'm having trouble with this problem. The question is: expand the function f(x)=x where x belongs to [0,2pi] into a real fourier series. Any help would be much appreciated thanks.

- Nov 24th 2008, 08:12 AMChris L T521
By definition of the Fourier Series, $\displaystyle f(x)=\frac{a_0}{2}+\sum_{n=1}^{\infty}a_n\cos(nx)+ b_n\sin(nx)$ where the Fourier coefficients are found as follows:

$\displaystyle a_0=\frac{1}{\pi}\int_0^{2\pi}f(x)\,dx$

$\displaystyle a_n=\frac{1}{\pi}\int_0^{2\pi}f(x)\cos(nx)\,dx$

$\displaystyle b_n=\frac{1}{\pi}\int_0^{2\pi}f(x)\sin(nx)\,dx$

Try to find these Fourier Coefficients when $\displaystyle f(x)=x$...or is this where you're stuck?

--Chris - Nov 24th 2008, 08:35 AMmbbx5va2
Hi, thanks for the reply but i've just found a thread from someone else concerning the same question.