know the linearization L(x)=f(a)+deriv (a)(x-a) is originally the tangential line to f at x=a. So, we think that for x near a, L(x)=f(x). While the change in y=f(x)-f(a)=deriv f(a).
Change in x=deriv f(a)(x-a)
Change in y=d=L(x)=f(x)=deriv f(a)dx
Even with all this i still can't get these problems..
a.)Find the linearization of y=f(x)=sqr(1+x) at x=0
b.) Find dy
c.) Find dy when x=0 and dx=.2
d.) Estimate f(.2) by the linearization
thanks for your help!