hey guys i have a little problem i cant get my head around

i undertsand that

$\displaystyle y=uv'+vu'$

but this question

$\displaystyle (x-9)(x-3)^{0.5}$

thats (x-3)^0.5 which is root (i dont know how to root in the maths tags

but the answer i keep getting is

$\displaystyle (x-9)/(x-3)^{0.5} + (x-3)^{0.5}$

the real answer is $\displaystyle (3x-15)/(2(x-3)^{0.5})$