∫∫y^3 dA, where D is the triangular region with vertices

D

(0,0),(3,1) and (-2,5).

thankyou!

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- Nov 23rd 2008, 12:51 PMiwonderEvaluate triangular region...
∫∫y^3 dA, where D is the triangular region with vertices

D

(0,0),(3,1) and (-2,5).

thankyou! - Nov 23rd 2008, 01:10 PMKrizalid
Make a sketch, that's all, only then you'll be able to set up the double integral.

- Nov 23rd 2008, 02:01 PMiwonder
i understand, but the problem was that i was confused in how to set up the double integral. thankyou.

- Nov 23rd 2008, 10:05 PMiwonder
Do i need to seperate into two different integrals?

- Nov 24th 2008, 03:55 AMshawsend
Yes: $\displaystyle I=\int_{-2}^{0}\int_{f_1(x)}^{f_2(x)}y^3 dydx+\int_{0}^{3}\int_{f_3(x)}^{f_2(x)}y^3 dydx$

where $\displaystyle f_1, f_2, f_3$ are just the equations of the lines making up the triangle. You can figure out which line is what right?