6^x+1 = 4^2x + 1
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Originally Posted by Danihop Solve
6^x+1 = 4^2x + 1 start by subtracting 1 from both sides and taking the log
Collect your x's and factor
Now by the zero factor theorem we have x=0.
I was trying to solve this problem a different way - I am at a loss - I don't know where to go from here - HELP PLEASE!
What is wrong with TheEmptySet's response? Please try to be a bit more specific.
Also, I am curious ... Is your problem: ... or ...
TheEmptySet solved the second one for you.
It is the first problem
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