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Math Help - exponential powers

  1. #1
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    Cool exponential powers

    Solve

    6^x+1 = 4^2x + 1
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  2. #2
    Behold, the power of SARDINES!
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    Quote Originally Posted by Danihop View Post
    Solve

    6^x+1 = 4^2x + 1
    start by subtracting 1 from both sides and taking the log

    6^x=4^{2x} \implies \ln(6^x)=\ln(4^{2x}) \implies x\ln(6)=2x\ln(4)

    Collect your x's and factor

    x\ln(6)-2x\ln(4)=0 \implies x(ln(6)-2ln(4))=0

    Now by the zero factor theorem we have x=0.

    Good luck
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  3. #3
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    I was trying to solve this problem a different way - I am at a loss - I don't know where to go from here - HELP PLEASE!
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  4. #4
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    What is wrong with TheEmptySet's response? Please try to be a bit more specific.

    Also, I am curious ... Is your problem: 6^{x+1} = 4^{2x+1} ... or ... 6^x + 1 = 4^{2x} + 1

    TheEmptySet solved the second one for you.
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  5. #5
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    It is the first problem
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