# Thread: definite integral?

1. ## definite integral?

integral from 1 to 4

(u-2)/sqrt(u)

I tried doing.. $(u-2)(u^{{-1/2}})$ and I ended up getting -3/4 but the answer is 2/3..

2. Originally Posted by elpermic
integral from 1 to 4

(u-2)/sqrt(u)

I tried doing.. $(u-2)(u^{{-1/2}})$ and I ended up getting -3/4 but the answer is 2/3..
$\int_1^4\frac{u-2}{\sqrt{u}}du=\int_1^4\bigg[\sqrt{u}-\frac{2}{\sqrt{u}}\bigg]du$