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Math Help - definite integral?

  1. #1
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    definite integral?

    integral from 1 to 4

    (u-2)/sqrt(u)

    I tried doing.. (u-2)(u^{{-1/2}}) and I ended up getting -3/4 but the answer is 2/3..
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  2. #2
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by elpermic View Post
    integral from 1 to 4

    (u-2)/sqrt(u)

    I tried doing.. (u-2)(u^{{-1/2}}) and I ended up getting -3/4 but the answer is 2/3..
    \int_1^4\frac{u-2}{\sqrt{u}}du=\int_1^4\bigg[\sqrt{u}-\frac{2}{\sqrt{u}}\bigg]du
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