I have found the slant asymptote of to be . Somehow, on it's graph, the slant looks totally off. What is the problem with my math? The factored form that was given is . Thanks!

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- Nov 22nd 2008, 10:03 PMnivek516Asymptote Question...
I have found the slant asymptote of to be . Somehow, on it's graph, the slant looks totally off. What is the problem with my math? The factored form that was given is . Thanks!

- Nov 22nd 2008, 10:59 PMmr fantastic
- Nov 22nd 2008, 11:01 PMmmm4444bot
Hello nivek:

Your math looks fine; the equation of the slant asymptote is y = x + 3.

(There is a typographical error in your factored form; the exponent in the denominator should be 3.)

What do you mean by saying that the slant on your graph is off?

The slope is one; if the scales on both axes are the same, then the graph of y = x + 3 should make a 45-degree angle with the horizontal axis.

Cheers,

~ Mark (Hi) - Nov 23rd 2008, 08:41 AMnivek516
**Yes, I typed in the wrong equation in my post. When I say the asymptote is off, I mean that the graph in quadrant 1 begins at around x=3 and avoids the asymptote. As , the graph starts to acknowlege the aymptote. Take a look. Could you explain why this happens?**