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Math Help - derivative check

  1. #1
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    derivative check

     <br />
y = \cot \sqrt{x} = cot(x)^\frac{1}{2}<br />

     <br />
y' = -csc(x)^\frac{1}{2} \cdot \frac{1}{2}x^\frac{-1}{2}<br />

    this correct? thank you
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  2. #2
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    Quote Originally Posted by jvignacio View Post
     <br />
y = \cot \sqrt{x} = cot(x)^\frac{1}{2}<br />

     <br />
y' = -csc(x)^\frac{1}{2} \cdot \frac{1}{2}x^\frac{-1}{2}<br />

    this correct? thank you
    not quite ...

    \frac{d}{dx} \cot{u} = -\csc^2{u} \cdot \frac{du}{dx}
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