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Math Help - derivative help please

  1. #1
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    derivative help please

     <br />
y = sec^2x - tan^2x<br />


    any help with this one much appreciated..
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  2. #2
    o_O
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    Note that: \color{blue} \sec ^2 x = 1 + \tan ^2 x

    So: y \ = \ {\color{blue}\sec^2 x} - tan^2 x \ = \ {\color{blue}(1 + \tan^2 x)} - \tan^2 x \ = \ 1
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  3. #3
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    Quote Originally Posted by o_O View Post
    Note that: \color{blue} \sec ^2 x = 1 + \tan ^2 x

    So: y \ = \ {\color{blue}\sec^2 x} - tan^2 x \ = \ {\color{blue}(1 + \tan^2 x)} - \tan^2 x \ = \ 1
    thanks mate.
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