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Math Help - Indefinite Integral (Calculus I)

  1. #1
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    Indefinite Integral (Calculus I)

    f(-8/x^7)dx

    The antiderivative of x^7 is x^8/8 but I have no idea what to do with the -8 in the original problem

    Thanks in advance..
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  2. #2
    o_O
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    The 8 is simply a constant. Just pull it out: \int \frac{8}{x^7} \ dx \ = \ 8 \int \frac{1}{x^7} \ dx \ = \ 8 \int x^{-7} \ dx
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