# Thread: Indefinite Integral (Calculus I)

1. ## Indefinite Integral (Calculus I)

f(-8/x^7)dx

The antiderivative of x^7 is x^8/8 but I have no idea what to do with the -8 in the original problem

2. The 8 is simply a constant. Just pull it out: $\int \frac{8}{x^7} \ dx \ = \ 8 \int \frac{1}{x^7} \ dx \ = \ 8 \int x^{-7} \ dx$