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Math Help - First year Calculus question

  1. #1
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    First year Calculus question

    I hate math, and suck at it, but I have to do it. I'm stuck on only one question on my current assignment. It looks really simple, but I've tried it a couple different ways, and I end up hitting a brick wall. Here it is;

    2. Does the equation 3x^3 - sin(x) + 3 = 0 have a solution?
    I haven't been able to find a value for x, and if it doesn't have a solution, I'm not sure how to show that... Can anyone help?

    We've been mostly dealing with limits so far, so this question kind of threw me for a loop. I'm not sure how to isolate x...
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  2. #2
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    Hello, Sucker Punch!

    2. Does the equation 3x - sin(x) + 3 = 0 have a solution?

    If that's the exact question, they did not ask for the solution(s).
    If they want a Yes-or-No answer, the answer is: Yes.

    We cannot solve for x; we can only approximate the value.

    We have: .3x + 3 .= .sin(x)
    . . and we want the intersection(s) of the curves: .y = 3x + 3 .and .y = sin(x).

    If we sketch the two graphs, we find an intersection in Quadrant 3.

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  3. #3
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    aw geez, you're right.

    It isn't even asking for a value. Thanks so much, this has been driving me out of my mind.

    I should have known too, we've been dealing with continous functions, and a lot of that is determining whether there is a proper answer or not.
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