This is the question/additional information copied out from my teacher:

Question: Find the equation of the line through (2,1) tangent to

y=x^3 - 6x + 5

Note: The given point (2,1) is NOT on the graph.

Tip: Use slope = (y2-y1)/(x2-x1) = dy/dx

Can anybody show how to do this?

My work:

y' = 3x^2 - 6

= 3(2)^2 - 6

= 6

(y-y1) = m(x-x1)

y-1 = 6(x-2)

My work is wrong...