evaluate the integral by reversing the order of integration

*please forgive me I don't know how to show integrals on here

this is a double integral

integral from 0 to 1 integral from 6y to 6 of e^x^2 dxdy

I changed the bounds to

x is between 0 and 6

y is between x/6 and 1

i get stuck on the integral between 0and 6 e^x^2(1-x/6)dx

I tried substitution but I wind up with $\displaystyle e^u/(2x)-e^u/12$ which doesn't work

How do I integrate this?