Can someone please show me how to get started with this one? Find the area between $\displaystyle y=3/(3x+2)$, $\displaystyle y=-6$, $\displaystyle x=2$, $\displaystyle x=3$
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$\displaystyle A = \int_2^3 \frac{3}{3x+2} - (-6) \, dx$
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