Find the derivative of 1 / square root of 2x

from first principles.

hellp !

xx

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- November 18th 2008, 06:12 AMJen1603Differentiation - First Principles
Find the derivative of 1 / square root of 2x

from first principles.

hellp !

xx - November 18th 2008, 07:45 AMJhevon
when you see "from first principles" they are talking about using the definition of the derivative.

there are two (equivalent) definitions:

if this is the definition you have been taught, then you are required to find the limit

alternatively, you may use the definition

in this case you are required to find the limit

(and replace with when finished)

Notation: and mean "the derivative of (with respect to )" and "the derivative of (with respect to x) at the point " respectively.

here of course, - November 19th 2008, 04:54 AMJen1603
I got as far as the first f '(x) equation but i wasnt sure how to simplify it with the two fractions and the square roots

- November 19th 2008, 07:48 AMJhevon
- November 19th 2008, 10:51 AMJen1603
i had tried multiply by the conjugate , but firstly im unsure how to combine the fractions and therefore it all gets a bit messy. could you show me ?

- November 19th 2008, 03:35 PMJhevon
- November 19th 2008, 03:43 PMJen1603
Thanks , so then i multiplyed by the conjugate .

so ive ended up with 2x - 2(x + h) on the top , but a really mess denominator. how do i simplify that ? - November 19th 2008, 03:45 PMJhevon
- November 19th 2008, 03:46 PMJen1603
how do you get h out of the denominator then ?

- November 19th 2008, 04:13 PMJhevon
- November 19th 2008, 04:16 PMJen1603
yeah , well i think i did = /

i multiplyed it by its conjugate over itself

and got 2x - 2 (x + h)

on the top , and then a mess on the bottom. and now im not sure what to do - November 19th 2008, 04:18 PMJhevon
- November 19th 2008, 04:20 PMJen1603
well i was getting confused about that aswell

because the x's cancel , so your left with -2h ...but then its as h tends to 0 , so would that not make the numerator zero ? - November 19th 2008, 04:23 PMJhevon
- November 19th 2008, 04:25 PMJen1603
cancel the h with the h on the denominator ?

but what about the h's that are inside square roots on the denominator ?