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Math Help - Limit of rational function factored but still indeterminate

  1. #1
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    Limit of rational function factored but still indeterminate

    Okay here is my problem,
    Lim X->2 (x^3 - 3x^2 -10x + 24)/(x^3 -4x^2 + x +6)
    so I went about factoring it using rational roots theorem and I got
    [(x-1)(x-6)(x+4)]/[(x-2)(x-3)(x+1)]
    So here I am and none of these factors cancel, someone please help me.
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  2. #2
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    Perhaps L'Hopital's rule will work.
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  3. #3
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by Boss_Tycoon View Post
    Okay here is my problem,
    Lim X->2 (x^3 - 3x^2 -10x + 24)/(x^3 -4x^2 + x +6)
    so I went about factoring it using rational roots theorem and I got
    [(x-1)(x-6)(x+4)]/[(x-2)(x-3)(x+1)]
    So here I am and none of these factors cancel, someone please help me.
    You factored it wrong

    \frac{x^3-3x^2-10x+24}{x^3-4x^2+x+6}=\frac{(x-4)(x+3)}{(x-3)(x+1)}
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  4. #4
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    Thanks, I made a dumb mistake I should have multiplied it out to check.
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