Results 1 to 2 of 2

Math Help - laplace help please very urgent

  1. #1
    Newbie
    Joined
    Nov 2008
    Posts
    1

    laplace help please very urgent

    Please can someone help me out of my misery.

    My question is how can I solve this equation:

    2CE e-3at u(t)-u(t-2t)

    I have replaced t with t= [(t-2T)+2T]

    now I have q(t) = 2CE e-3a[(t-2T)+2T] u[(t-2T)+2T]-u(t-2T)

    so I have crossed out the delay of 2T = e-2Ts

    so I am left with q(t) = 2CE e-3a(t+2T) u(t+2T)-u(t)

    I am now lost and have no idea what to do next.

    Please can someone put me out of my misery.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Flow Master
    mr fantastic's Avatar
    Joined
    Dec 2007
    From
    Zeitgeist
    Posts
    16,948
    Thanks
    5
    Quote Originally Posted by darren1971 View Post
    Please can someone help me out of my misery.

    My question is how can I solve this equation:

    2CE e-3at u(t)-u(t-2t)

    I have replaced t with t= [(t-2T)+2T]

    now I have q(t) = 2CE e-3a[(t-2T)+2T] u[(t-2T)+2T]-u(t-2T)

    so I have crossed out the delay of 2T = e-2Ts

    so I am left with q(t) = 2CE e-3a(t+2T) u(t+2T)-u(t)

    I am now lost and have no idea what to do next.

    Please can someone put me out of my misery.
    No-one has probably replied so far because, like me, they can't make sense of what you've posted. Problems with what you've posted include (but are not limited to):

    1. There's no equation given to solve. Equations have an equal sign (=) in them.

    2. What is CE meant to represent?

    3. Is e-3at meant to be e^{-3at}. If so, it should at least be written as e^(-3at).

    4. "I have replaced t with t= [(t-2T)+2T]" makes no sense.

    If you want help, especially urgent help, you will need to be much much clearer.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Laplace/Inverse Laplace Questions
    Posted in the Differential Equations Forum
    Replies: 2
    Last Post: August 14th 2010, 12:29 PM
  2. Laplace of cosh (sorry urgent)
    Posted in the Differential Equations Forum
    Replies: 2
    Last Post: May 11th 2010, 09:43 PM
  3. Semi urgent - Laplace Transform
    Posted in the Calculus Forum
    Replies: 5
    Last Post: April 27th 2010, 09:07 PM
  4. Urgent!!!help with attempted questions - urgent
    Posted in the Statistics Forum
    Replies: 2
    Last Post: February 28th 2010, 01:29 AM
  5. Replies: 7
    Last Post: April 27th 2007, 10:22 AM

Search Tags


/mathhelpforum @mathhelpforum