Question states, using geometric considerations, what does $\displaystyle \int\limits_0^1 {\sqrt {1 - x^2 } } + 2dx$ equal

I can see that between zero and one that sqrt (1-x^2) is quadrant of a circle so the area would be 1/4*pi*r^2 but where does the +2 come in, I see it would move the circle up the y axis by 2. But I'm stuck