Thread: General Antiderivatives

Just got this question wrong, I make a mistake somewhere and I need some pointing out where to where it is. Heres the problem first

Find the most general antiderivative of the function

Alright.. Here's my work:

First I converted the cube root x^2 and sqrt x^9 to :

f(x) = x^2/3 - x^9/2

Then using the antiderivative rule of , I got:

f(x) = (x^5/3) / (5/3) - (x^11/2) / (11/2) + C

simplifying that I get :

3/5x^(5/3) - 2/11x^(11/2) + C

... I ended up getting the answer wrong

Help is greatly appreciated

Originally Posted by endiv

Just got this question wrong, I make a mistake somewhere and I need some pointing out where to where it is. Heres the problem first

Alright.. Here's my work:

First I converted the cube root x^2 and sqrt x^9 to :

f(x) = x^2/3 - x^9/2

Then using the antiderivative rule of , I got:

f(x) = (x^5/3) / (5/3) - (x^11/2) / (11/2) + C

simplifying that I get :

3/5x^(5/3) - 2/11x^(11/2) + C

... I ended up getting the answer wrong

Help is greatly appreciated

your answer is correct. the integral is

Oh, wow. My mistake was putting a little c instead of a capital C, which resulted my in a wrong answer :|. Thanks!

Originally Posted by endiv

Oh, wow. My mistake was putting a little c instead of a capital C, which resulted my in a wrong answer :|. Thanks!

i don't see why that should make a difference, but ok. maybe whatever you are typing the answer into is case sensitive