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Math Help - Integrating/Quotient Rule?

  1. #1
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    Integrating/Quotient Rule?

    Can someone please help me; my math professor did not teach us how to integrate functions that were being divided.

    The instructions for this problem were to find the anti-derivative.
    Would you use the reverse of the quotient rule for this problem?
    How would you do it?

    Can anyone please give me step by step instruction on how to solve this?

    Thanks in advance!
    Last edited by overduex; November 16th 2008 at 09:55 AM. Reason: Forgot an important part, sorry
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  2. #2
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    Sorry, I'm so scatter-brained forgot to put up the problem.
    That's an integration sign, by the way.
    Attached Thumbnails Attached Thumbnails Integrating/Quotient Rule?-integralll.jpg  
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  3. #3
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    Smile

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  4. #4
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    I have another question...

    Quote Originally Posted by Math_Helper View Post
    Click image for larger version. 

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    Thank you. So would you always try to factor binomials, in hopes that it would cancel out?

    I have another problem that says (x+2)^2 / x^4
    so to find the antiderivative of this problem it would be:
    (x+2)(x+2)/x^4
    then, I'm stuck. Nothing really cancels out.
    If its not too much trouble can you explain how to do this one too? you don't have to solve it, words are fine.
    thank you
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  5. #5
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    Thank you. So would you always try to factor binomials, in hopes that it would cancel out?

    This is not always possible, sometimes you have to divide the Numerator by Denumerator and you obtain a whole Number plus fraction, like in example below

    Integrating/Quotient Rule?-untitled.jpg
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  6. #6
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    I have another problem that says (x+2)^2 / x^4
    so to find the antiderivative of this problem it would be:
    (x+2)(x+2)/x^4

    In previous example it was degree(numerator) > degree(denumerator) in that case you mas to extract the whole from the fraction, here
    In this example we have degree((x+2)^2) < degree(x^4) and you can not to extract the whole number

    Integrating/Quotient Rule?-untitled.jpg
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