Find the derivative of s= 2x^2 (3-x^3)^6

using product rule

ds/dx = (3-x^3)^6(6x^2) + 2x^3(6)(-3x^2)(3-x^3)^5

ds/dx= (3-x^3)^5(6x^2(3-x^3) -36x^5)

ds/dx= (3-x^3)^5(18x^2-6x^5-36x^5)

(3-x^3)^5(18x^2-42x^5)

I can't get the answer (3-x^3)^5 (12x-40x^4)