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Math Help - finding the dy/dx

  1. #1
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    finding the dy/dx

    i am having trouble with find the dy/dx for

    1) y= 1/3x3

    2) y= 3/4x5

    3) y=4 square root_/x3


    please note the small numbers are powers.
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  2. #2
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    Quote Originally Posted by rpatel View Post
    i am having trouble with find the dy/dx for

    1) y= 1/3x3
    2) y= 3/4x5
    3) y=4 square root_/x3


    please note the small numbers are powers.
    Hello,

    if y = a*x^r, a, r are real numbers, then dy/dx= a*r*x^(r-1)

    With your problems you'll get:
    1) dy/dx=(1/3)*3*x^2 = x^2
    2) dy/dx = 15/4*x^4
    And now I'm only guessing:
    Transform the root into a power: y = x^(1/4)
    3) dy/dx = (1/4)*x^(-3/4)

    Greetings

    EB
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