Thread: finding the dy/dx

i am having trouble with find the dy/dx for

1) y= 1/3x3

2) y= 3/4x5

3) y=4 square root_/x3


please note the small numbers are powers.

Originally Posted by rpatel

i am having trouble with find the dy/dx for

1) y= 1/3x3
2) y= 3/4x5
3) y=4 square root_/x3


please note the small numbers are powers.

Hello,

if y = a*x^r, a, r are real numbers, then dy/dx= a*r*x^(r-1)

With your problems you'll get:
1) dy/dx=(1/3)*3*x^2 = x^2
2) dy/dx = 15/4*x^4
And now I'm only guessing:
Transform the root into a power: y = x^(1/4)
3) dy/dx = (1/4)*x^(-3/4)

Greetings

EB