Hi

For y=2/(x-1), how do I exactly find the turning pts?

I tried following my teacher's way by first turning it into a quadratic equation and finding its discriminant:

y(x-1) = 2

yx - y - 2 = 0

discriminant = y^2

For x to be real then its discriminant must be greater or equal to 0

i.e. y^2 is greater than or equal to 0

This becomes y is greater than or equal to 0.

When y = 0, equation becomes 0 = 2.

**That's where I'm stuck. For the other graphs, my teacher's method allowed me to find the turning points. For this one (the first question ), it doesn't work.**
Could someone please help and tell me how to find the turning pt here?