Thread: How would you tackle this question? [Area]

I'm not asking you to do it for me (unless you want to ), but i just dont know what to do, so what would you do..?

Heres the Q:

For the function , the ratio of area A:Area B is n:1, where A is the area from y = 0 to 1 and the y axis, and B is the area from x = 0 to 1 and the x axis. As shown:


Is this ratio true for the general case from x = a to b such that a < b, and for the regions defined below?

Area A: , , and the y axis
Area B: , , and the x axis

If so prove it; if not why not?

___

Once again, I'm not asking you to do it for me, I just need help as to what to do

I've proven that the ratio holds for like x = 0 to 5, or 2 to 7, but what else do i need to do?/ What is the question really asking for

Hello, jhomie!

For the function: , the ratio of area to area is
where is the area from and the y-axis,
and is the area from and the x-axis.

Code:

      |
     1+ - - - - -*
      |::::::::::|
      |::: A :::*|
      |::::::::* |
      |::::::*   |
      |:::*   B  |
    --*----------+--
      |           1

Area A




Area B




Therefore: .

Originally Posted by Soroban

Hello, jhomie!


Area A




Area B




Therefore: .

yea, i understand that. right?

But that is just for 0 to 1, theres still a and b both -ve, a -ve b positive, then changing n so that it is positive integer, negative integers, fraction and irrational. Is that what i'm supposed to do?

For i cant seem to get the same ratio. I might be doing something wrong, but dunno