Hello, endiv!
There's some tricky algebra in this one . . .
Differentiate and equal to zero . . .Find critical numbers for: .
. .
We have: .
Multiply by
Factor: .
Therefore, the critical values are at: .
Find critical numbers for x^(4/5) * (x-1)^2?
If you could help out, please. I've already done most of the work, but I'm not too sure on where to go and how to work with the problem to get the critical numbers.
(1). The derivative of the problem. Using the product rule you get
x^(4/5) * 2(x-1) + (x-1)^2 * 4/5x^-1/5
here's where I'm stuck.. the factoring
Relating to the solutions manual for a similar problem ( x^(4/5) * (x-4)^2 ), I know that I'll be able to factor it by:
1/5x^-1/5 * (x-1)
This is where I'm stuck... factoring will I get:
(1/5)x^-(1/5)*(x-1) [ 5 * x * 1 + (x-1) *4] ????
can anyone give me a push on this? I should be able to solve this step after the factoring.
-Thanks