Hi all,
I have the lines:
A: x = 1 + 2t, y = 2+ 3t, z = 3 + 4t
B: x-2 = (y-4)/2 = (-z -1)/4
I am having trouble determining the coordinates of the point of intersection of A and B.
Well i found B in parametric form first:
x = 2 + t, y = 4 +2t, Z = -4 -4t
and then i equated each component....
e.g 1 + 2t = 2 + t; 2 +3t = 4 +2t
the t values differed for each component and thus i thought there was no point of intersection. However, in the answer there is a point of intersection at (1,2,3). So i am lost here...
Thanks in advance,
ArTiCk