I've been trying to do this for quite a while now and keep going around in circles, anyone offer help? $\displaystyle \int\frac{1+tanx}{1+cosx}dx$ Isk
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Originally Posted by Isktaine I've been trying to do this for quite a while now and keep going around in circles, anyone offer help? $\displaystyle \int\frac{1+tanx}{1+cosx}dx$ Isk This has been aswered somewhere recently, but $\displaystyle \int\frac{1+\tan(x)}{1+\cos(x)}dx=\int\bigg[\frac{1}{1+\cos(x)}+\frac{\sin(x)}{\cos(x)(\cos(x) +1)}\bigg]dx$ Can you take it from there?
Over here.
Thank you both!
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