Find the intervals on which the function is increasing and decreasing.

y= x^(1/4) (x+4)

I took the derivative of the function, it is (1/4)x^(-3/4)

that's all I know.

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- November 14th 2008, 06:46 PMSeigihow to find the interval where it's increasing/decreasing?
Find the intervals on which the function is increasing and decreasing.

y= x^(1/4) (x+4)

I took the derivative of the function, it is (1/4)x^(-3/4)

that's all I know. - November 14th 2008, 07:14 PMTKHunny
That's not the derivative. What happened to the (x+4)?

Once you find the derivative, where is it positive? That's where the function is increasing. Confusion on this point is not encouraging. It is a fundamental property of the derivative. You would do well to back up and re-read a few chapters. - November 14th 2008, 07:32 PMSeigi
i guess i did it wrong, what's the derivative then?

- November 14th 2008, 07:36 PMo_O
You tell us:

- November 14th 2008, 07:44 PMSeigi
oh, thank you, you set it equal to zero, and find where it is increasing/decreasing right? how do you do that?

- December 22nd 2008, 03:10 PMmr fantastic