Consider the vector function r(t) =< 4t + 1, t2 − 3t, cos(t) >.
(a) Find the unit tangent vector T at (1, 0, 1)
I know that T = r'(t)/|r-(t)|
and r'(t) = < 4, 2t-3, -sin(t)>
I'm not sure why the book plugs in 0 for t.
Thanks in advance
Consider the vector function r(t) =< 4t + 1, t2 − 3t, cos(t) >.
(a) Find the unit tangent vector T at (1, 0, 1)
I know that T = r'(t)/|r-(t)|
and r'(t) = < 4, 2t-3, -sin(t)>
I'm not sure why the book plugs in 0 for t.
Thanks in advance