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Math Help - triple integral..

  1. #1
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    triple integral..

    How to evaluate where is the box determined by
    , , and ?
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  2. #2
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by iwonder View Post
    How to evaluate where is the box determined by
    , , and ?
    ...It would just be \int_0^5\int_0^2\int_0^1{ye^{-xy}}dxdydz
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  3. #3
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    After i do the calculations, i still can not find the answer. Can someone help me out? thankyou!
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  4. #4
    Moo
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    Hello,
    Quote Originally Posted by iwonder View Post
    After i do the calculations, i still can not find the answer. Can someone help me out? thankyou!
    The integral can be written this way :

    \left(\int_0^5 dz\right) \left(\int_0^2 \int_0^1 ye^{-xy} ~ dx dy\right)
    because there is no "z" in the integrand.

    Now for the second integral, it can be written this way (maybe you'll see more precisely how to proceed) :

    \int_0^2 \left(\int_0^1 ye^{-xy} ~ dx\right) ~ dy

    In order to calculate the integral in the parentheses, if you don't know what to do, make a substitution t=-xy



    If you still don't get the answer, then it would be nice you show your work
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