Given: f(x) = e^(-2x^2)
f'(x) evaluated as -4xe^(-2x^2)
Now, every example I've seen thus far is a polynomial function, which makes it easy to find the roots and determine what interval it's increasing or decreasing, not so here. Any tips?
mr fantastic, thank you for your reply. I've worked through the problem and studied notes a little more carefully. The second derivative test returns concave upward for all real values, which is correct according to the graph of the original function.
f"(x) = 4e^(2x^2)[(1+4x^2)]
I set 1+4x^2 to zero as my two critical points and tested away.
Not too sure how you evaluated 4xe^(2x^2) = 0
From the graph, I know it has to be zero, but algebraically I'm not quite sure how to work that out (other than the assumption it HAS to equal zero)