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Math Help - area of enclosed region with e

  1. #1
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    area of enclosed region with e

    Problem:

    Sketch the region enclosed by y=e^3x, y=e^6x, and x=1. Decide whether to integrate with respect to x or y. Then find the area of the region.


    The answer I got was 60.543, which is wrong. I did it by getting this integral:

    integral(e^6x - e^3x) over [0,1]
    (1/6)(e^6x) - (1/3)(e^3x) over [0,1]

    How do I solve this properly?
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  2. #2
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    A = \left(\frac{e^6}{6} - \frac{e^3}{3}\right) - \left(\frac{1}{6} - \frac{1}{3}\right)

    you forgot to subtract the value \left(\frac{1}{6} - \frac{1}{3}\right) ...

    e^0 = 1 , remember?
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