# area of enclosed region with e

• November 13th 2008, 05:47 PM
backtoreality15
area of enclosed region with e
Problem:

Sketch the region enclosed by y=e^3x, y=e^6x, and x=1. Decide whether to integrate with respect to x or y. Then find the area of the region.

The answer I got was 60.543, which is wrong. I did it by getting this integral:

integral(e^6x - e^3x) over [0,1]
(1/6)(e^6x) - (1/3)(e^3x) over [0,1]

How do I solve this properly? (Crying)
• November 13th 2008, 06:32 PM
skeeter
$A = \left(\frac{e^6}{6} - \frac{e^3}{3}\right) - \left(\frac{1}{6} - \frac{1}{3}\right)$

you forgot to subtract the value $\left(\frac{1}{6} - \frac{1}{3}\right)$ ...

$e^0 = 1$ , remember?