Sketch the region enclosed by y=e^3x, y=e^6x, and x=1. Decide whether to integrate with respect to x or y. Then find the area of the region.
The answer I got was 60.543, which is wrong. I did it by getting this integral:
integral(e^6x - e^3x) over [0,1]
(1/6)(e^6x) - (1/3)(e^3x) over [0,1]
How do I solve this properly? (Crying)