I need to find the horizontal asymptote for this function:

y= x/((sqrt)x^2-1)

the method we're supposed to use is multiple the numerator and denominator by (1/x). I just have some problems when square roots are involved.

Printable View

- November 13th 2008, 11:57 AMdm10Horizontal Asymptote
I need to find the horizontal asymptote for this function:

y= x/((sqrt)x^2-1)

the method we're supposed to use is multiple the numerator and denominator by (1/x). I just have some problems when square roots are involved. - November 13th 2008, 12:49 PMJameson
As long as you don't have to be super formal in your method, here's a way to do it.

Now you can cancel out your x's and evaluate the new limit as x approaches infinity of , which should be trivial.