solid limited by: $\displaystyle z=9-x^2$ , $\displaystyle z=0,x=0,y=x,y=3$ Answer: $\displaystyle \frac{135}{4}$
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why build this integral?
$\displaystyle \int_{0}^{3}\int_{x}^{3}\int_{0}^{9-x^{2}}dzdydx$
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