Results 1 to 3 of 3

Math Help - stuck on a f'(x) problem

  1. #1
    Newbie
    Joined
    Nov 2008
    Posts
    2

    stuck on a f'(x) problem

    f(x)= x over root x^2+1 (all of its in a root)

    I can get this far (x^2+1)^1/2(1) - (x)(1/2)(x^2+1)^-1/2(2x) all over (x+1)^1/4

    this breaks down to (now i'm not sure if this is right) (x^2+1)^1/2-x^2 over (x+1)^1/4(x^2+1)^1/2

    am i even on the right track?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Newbie
    Joined
    Nov 2008
    Posts
    5
    using product or quotient rule will do the trick . in product rule , just assume x as first fn , and 1/root(x^2+1) as second fn and differentiate
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor

    Joined
    Apr 2005
    Posts
    15,987
    Thanks
    1650
    Quote Originally Posted by lblue54 View Post
    f(x)= x over root x^2+1 (all of its in a root)

    I can get this far (x^2+1)^1/2(1) - (x)(1/2)(x^2+1)^-1/2(2x) all over (x+1)^1/4
    Where did you get (x+1)^(1/4)? Using the quotient rule, the denominator is squared. ((x+1)^(1/2))^2= x+ 1, not (x+1)^(1/4).

    this breaks down to (now i'm not sure if this is right) (x^2+1)^1/2-x^2 over (x+1)^1/4(x^2+1)^1/2

    am i even on the right track?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. stuck on this problem for cal 1
    Posted in the Calculus Forum
    Replies: 3
    Last Post: September 16th 2008, 06:50 AM
  2. Stuck on a problem
    Posted in the Algebra Forum
    Replies: 2
    Last Post: August 28th 2008, 11:36 AM
  3. here is another problem that i stuck on
    Posted in the Algebra Forum
    Replies: 2
    Last Post: June 28th 2007, 08:58 PM
  4. I got stuck on this problem: C(n,6)=C(n,9)
    Posted in the Algebra Forum
    Replies: 3
    Last Post: June 7th 2007, 07:22 AM
  5. Stuck on an SAT problem
    Posted in the Algebra Forum
    Replies: 1
    Last Post: March 30th 2006, 12:59 AM

Search Tags


/mathhelpforum @mathhelpforum