1. ## Logarithmic diff

Here is a problem that I am unsure how to proceed..

Differentiate

3^x

2. $(a^x)'=a^x\cdot\ln a$

3. Hi

Originally Posted by dankelly07
Here is a problem that I am unsure how to proceed..

Differentiate

3^x
This is simple, because

$3^x = e^{x*ln(3)}$

$[e^{x*ln(3)}] ' = ln(3) * [e^{x*ln(3)}] = ln(3) *3^x$