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Math Help - Logarithmic diff

  1. #1
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    Logarithmic diff

    Here is a problem that I am unsure how to proceed..

    Differentiate

    3^x
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  2. #2
    MHF Contributor red_dog's Avatar
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    (a^x)'=a^x\cdot\ln a
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  3. #3
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    Hi

    Quote Originally Posted by dankelly07 View Post
    Here is a problem that I am unsure how to proceed..

    Differentiate

    3^x
    This is simple, because

    3^x = e^{x*ln(3)}

    [e^{x*ln(3)}] ' = ln(3) * [e^{x*ln(3)}] = ln(3) *3^x
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