Use the answer to the Fourier series: for Compute sum: [(-1)^n] / (2n+1) Some starting points would be greatly appreciated!!
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Try putting .
Originally Posted by Opalg Try putting . Thank you, I've tried this. However, I still don't see where to get SUM 1/(2n+1) I think I am missing a fundamental step. Any ideas?
Originally Posted by Chitownmegs Thank you, I've tried this. However, I still don't see where to get SUM 1/(2n+1) I think I am missing a fundamental step. Any ideas? , and in general Therefore in the sum , only the odd-numbered terms are nonzero. So try putting n=2m+1, with the sum going from m=1 to ∞.
Last edited by Opalg; November 13th 2008 at 02:04 PM. Reason: Silly mistake, as so often
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