any1 wanna show me how to find the inverse laplace transform of (e^-2s)/(s(s^2+2)) .... i cant seem to solve it, am i missing something here?
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Originally Posted by ah-bee any1 wanna show me how to find the inverse laplace transform of (e^-2s)/(s(s^2+2)) .... i cant seem to solve it, am i missing something here? $\displaystyle \frac{e^{-2s}}{s(s^2 + 2)} = \frac{1}{2} \, e^{-2s}\, \left( \frac{1}{s} - \frac{1}{s^2 + 2}\right) = \frac{1}{2} \, e^{-2s} \, \frac{1}{s} - \frac{1}{2} \, e^{-2s} \, \frac{s}{s^2 + 2} $. Now just apply the usual theorems to each term.
thanks a lot for that!
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