x= 1/sqrt(t-5) , y= t/(t-5) , for t in (5,infinite)
Follow Math Help Forum on Facebook and Google+
Hello, scottydoint! Square [1]: . Substitute into [2]: . Multiply by If , then: . The graph is an up-opening parabola, vertex at (0, 1) ... only the right half. Code: | * | | * | * | * | * 1 o | - + - - - - - - - |
| * | | * | * | * | * 1 o | - + - - - - - - - |
View Tag Cloud