divide the specified interval into n=4 subintervals of equal length and then compute using the Area under a curve with as a left endpoint of each subinterval f(x)=3x+1; [2,6]
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Each interval is: And since we're using left-end points, i.e. , we have: So plugging it all in:
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 \Delta x = \sum_{k=1}^4 f(x_{k-1}) (1) = f(x_0) + f(x_1) + f(x_2) + f(x_3) = \cdots)
