Why does the limit as t approaches infinity of [(-te-5t)/5]-[e^-5t/25]= 1/25? I keep getting infinities when I try to use l'Hospitals rule.
Follow Math Help Forum on Facebook and Google+
Originally Posted by sfgiants13 Why does the limit as t approaches infinity of [(-te-5t)/5]-[e^-5t/25]= 1/25? I keep getting infinities when I try to use l'Hospitals rule. Here is what you have posted: Is that really what you meant?
Originally Posted by Plato Here is what you have posted: Is that really what you meant? I don't know how to use the math tags but the equatino above isn't right. (-1/5) x te^-5t - (1/25) x e^-5t as t approaches infinity.
Originally Posted by sfgiants13 the equatino above isn't right. (-1/5) x te^-5t - (1/25) x e^-5t as t approaches infinity. Well it surely is the same to me. What is incorrect about the above?
I got -1/25 too for some reason but the book says it's convergant to 1/25. I'm thinking ti was just a math error in the book now...
Originally Posted by sfgiants13 I got -1/25 too for some reason but the book says it's convergant to 1/25. I'm thinking ti was just a math error in the book now... I think that there is indeed a typo but I think it is in that first minus sign.
View Tag Cloud