could some one explain about the dirichlet function ? I'm confused.

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- November 12th 2008, 11:11 AMsrinathmurthyDirichlet function
could some one explain about the dirichlet function ? I'm confused.

- November 12th 2008, 12:01 PMHallsofIvy
What do you want explained about it? There are several "Dirichlet" functions but the standard one is:

f(x)= 0 if x is rational, 1 if x is irrational.

That has the property that it is discontinuous for all x because in any interval around x, there exist both rational and irrational numbers, so values of 0 and 1 arbitrarily close to x. What is it that is confusing you? - November 13th 2008, 08:13 AMsrinathmurthy
there in an article in WIKI , [IMG]file:///C:/DOCUME%7E1/Admin/LOCALS%7E1/Temp/moz-screenshot-3.jpg[/IMG]

lim ( lim (cos k!pi) ^ 2j )

k-->inf j-->inf

I'd like to know how this reduces to the dirichlet function. form.

[IMG]file:///C:/DOCUME%7E1/Admin/LOCALS%7E1/Temp/moz-screenshot-1.jpg[/IMG][IMG]file:///C:/DOCUME%7E1/Admin/LOCALS%7E1/Temp/moz-screenshot-2.jpg[/IMG] - November 13th 2008, 08:44 AMHallsofIvy
Please post a link to that article. I cannot see the images you tried to post.

- November 16th 2008, 06:14 AMsrinathmurthy
Nowhere continuous function - Wikipedia, the free encyclopedia

here's the link , please explain. Who's the admin here? could anybody tell me? - November 16th 2008, 07:05 AMHallsofIvy
You mean ?

Suppose x is a rational number. Then x= m/n for integers m and n and, for k> n, k!/n is an integer. cosine of an integer times is either -1 or 1 and raised to an even power, 2j, is 1. Thus, for sufficiently large, k, that function is just 1 to the 2j power= 1. If x is irrational, then is never an integer so [tex]-1< cos(k!\pi x)< 1[tex]. Raising that to the 2j power, as j goes to infintiy gives 0. - November 19th 2008, 09:05 AMsrinathmurthy
Thank you.