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  1. #1
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    Question sine integral

    integration x sin x dx
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  2. #2
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by mindblowing View Post
    integration x sin x dx
    You can do this by parts:

    u=x and \,dv=\sin x\,dx

    Thus, \,du=\,dx and v=-\cos x

    Now I leave it for you to plug it into the integration by parts formula and simplify:

    \int u\,dv=uv-\int v\,du

    Can you take it from here?

    --Chris
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    Quote Originally Posted by mindblowing View Post
    integration x sin x dx
    \int x \sin x dx = \int x \left( -\cos x \right)' dx = -x\cos x - \int (x)'(-\cos x) dx = -x \cos x + \sin x + k
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