integration x sin x dx

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- Nov 12th 2008, 08:15 AMmindblowingsine integral
integration x sin x dx

- Nov 12th 2008, 08:30 AMChris L T521
You can do this by parts:

$\displaystyle u=x$ and $\displaystyle \,dv=\sin x\,dx$

Thus, $\displaystyle \,du=\,dx$ and $\displaystyle v=-\cos x$

Now I leave it for you to plug it into the integration by parts formula and simplify:

$\displaystyle \int u\,dv=uv-\int v\,du$

Can you take it from here?

--Chris - Nov 12th 2008, 12:52 PMThePerfectHacker