I have no clue how to do this problem. please help. A rectangle has one side on the x -axis and two vertices on the curve: 4/(2+x^2) Find the vertices of the rectangle with maximum area.
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Originally Posted by jojoferni244 I have no clue how to do this problem. please help. A rectangle has one side on the x -axis and two vertices on the curve: 4/(2+x^2) Find the vertices of the rectangle with maximum area. Let the rectangle be symmetric. It has vertices at (-a, 0) and (a, 0). Then the width of the rectangle is 2a and the height of the rectangle is . Then the area of the rectangle is . Use calculus to find the value of a that maximises A.
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