Find the area of the surface: The part of the surface z = 1+3x+2y^2 that lies above the triangle with vertices (0,0) (0,1) and (2,1)

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- November 11th 2008, 05:17 PMjlt1209Find the area of the surface ...
Find the area of the surface: The part of the surface z = 1+3x+2y^2 that lies above the triangle with vertices (0,0) (0,1) and (2,1)