1. ## integral

find an equation of the curve that satisfies the given conditions

At each point (x,y) on the curve the slope is 2x+1; the curve passes through the point (-3,0)

2. Originally Posted by vinson24
find an equation of the curve that satisfies the given conditions

At each point (x,y) on the curve the slope is 2x+1; the curve passes through the point (-3,0)
dy/dx = 2x+1

Integrate the function listed above and substitude the coordinates (-3,0) into the result. You will be able to find the equation of the curve. Hope it helps.

3. thank you got it my math was wrong

4. What is the actual answer to this..I am upset that somethings so simple stumped me for a minute.

5. dy/dx = 2x+1
y = x^2 + x + c ( after integration )
0 = (-3)^2 + (-3) + c ( now substitute x = -3 and y=0 to find c )
c = 6 should be -6
therefore the equation is, y = x^2 + x - 6 (ans)

6. no the answer is $y=x^2+x-6$

7. Sorry minor calculation error. Thread updated.

8. i did the same thing at first too

9. It is common to make careless mistakes in mathematics that's the reason we have to double check the equations again to prevent any careless mistakes from happening.