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Math Help - integral

  1. #1
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    integral

    find an equation of the curve that satisfies the given conditions

    At each point (x,y) on the curve the slope is 2x+1; the curve passes through the point (-3,0)
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  2. #2
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    Quote Originally Posted by vinson24 View Post
    find an equation of the curve that satisfies the given conditions

    At each point (x,y) on the curve the slope is 2x+1; the curve passes through the point (-3,0)
    dy/dx = 2x+1

    Integrate the function listed above and substitude the coordinates (-3,0) into the result. You will be able to find the equation of the curve. Hope it helps.
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  3. #3
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    thank you got it my math was wrong
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  4. #4
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    What is the actual answer to this..I am upset that somethings so simple stumped me for a minute.
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  5. #5
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    dy/dx = 2x+1
    y = x^2 + x + c ( after integration )
    0 = (-3)^2 + (-3) + c ( now substitute x = -3 and y=0 to find c )
    c = 6 should be -6
    therefore the equation is, y = x^2 + x - 6 (ans)
    Last edited by tester85; November 11th 2008 at 07:11 PM.
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  6. #6
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    no the answer is y=x^2+x-6
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  7. #7
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    Sorry minor calculation error. Thread updated.
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  8. #8
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    i did the same thing at first too
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  9. #9
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    It is common to make careless mistakes in mathematics that's the reason we have to double check the equations again to prevent any careless mistakes from happening.
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