Can someone please show me how to do this problem? I have the answer but do not understand the steps in order to arrive at it.
Integral 4r square root(6-r) dr
Answer: 8/5*(6-r)^5/2 - 16(6-r)^3/2 +C
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Do you know integration by parts?
If not, read Integration by Parts -- from Wolfram MathWorld.
If so, use it.
I read that but still can't get it to work out properly.
can you finish?
ok, but how do you get the 8/5 and the -16?
distribute the constant 4 ...
now back substitute (6-r) for u.
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