Show that: |f - g| is integrable.
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Originally Posted by Coda202 Show that: |f - g| is integrable. Well, it isn't in general! If you forgot to include the hypotheses that f and g are themselves integrable, then you can use the fact that |f- g|= f- g as long as f(x)> g(x) and |f- g|= g- f as long as f(x)< g(x).
Originally Posted by Coda202 Show that: |f - g| is integrable. If are integrable then are integrable. And if is integrable then is integrable. Therefore, if are integrable then is integrable and that implies is integrable.
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